Cheat Sheet Subnetting
Cheat Sheet Subnetting
Section titled “Cheat Sheet Subnetting”Referensi cepat untuk menghitung subnet, VLSM, dan memahami notasi CIDR dalam jaringan komputer.
1. Pengertian Subnet Mask
Section titled “1. Pengertian Subnet Mask”Subnet mask adalah angka 32-bit yang digunakan untuk membagi jaringan IP menjadi segmen-segmen lebih kecil (subnet).
Subnet mask terdiri dari:
- Bagian Network (1) — menentukan alamat jaringan
- Bagian Host (0) — menentukan alamat host dalam jaringan
Contoh:
Section titled “Contoh:”IP Address : 192.168.1.10Subnet Mask : 255.255.255.0 = /24 (11111111.11111111.11111111.00000000)
Network bits : 24 (semua 1)Host bits : 8 (semua 0)Kelas IP Address:
Section titled “Kelas IP Address:”| Kelas | Range | Default Mask | Penggunaan |
|---|---|---|---|
| A | 1.0.0.0 – 126.255.255.255 | /8 (255.0.0.0) | Jaringan besar |
| B | 128.0.0.0 – 191.255.255.255 | /16 (255.255.0.0) | Jaringan menengah |
| C | 192.0.0.0 – 223.255.255.255 | /24 (255.255.255.0) | Jaringan kecil |
| D | 224.0.0.0 – 239.255.255.255 | — | Multicast |
| E | 240.0.0.0 – 255.255.255.255 | — | Riset/Eksperimental |
IP Private (RFC 1918):
Section titled “IP Private (RFC 1918):”| Range | CIDR | Penggunaan |
|---|---|---|
| 10.0.0.0 – 10.255.255.255 | 10.0.0.0/8 | LAN besar |
| 172.16.0.0 – 172.31.255.255 | 172.16.0.0/12 | LAN menengah |
| 192.168.0.0 – 192.168.255.255 | 192.168.0.0/16 | LAN rumah/kantor |
2. Tabel Subnet Lengkap (/24 sampai /30)
Section titled “2. Tabel Subnet Lengkap (/24 sampai /30)”Class C (/24 – /30)
Section titled “Class C (/24 – /30)”| CIDR | Subnet Mask | Jumlah Host | Jumlah Subnet* | Blok |
|---|---|---|---|---|
| /24 | 255.255.255.0 | 254 | 1 | 256 |
| /25 | 255.255.255.128 | 126 | 2 | 128 |
| /26 | 255.255.255.192 | 62 | 4 | 64 |
| /27 | 255.255.255.224 | 30 | 8 | 32 |
| /28 | 255.255.255.240 | 14 | 16 | 16 |
| /29 | 255.255.255.248 | 6 | 32 | 8 |
| /30 | 255.255.255.252 | 2 | 64 | 4 |
*Jumlah subnet dari network /24
Rumus Penting:
Section titled “Rumus Penting:”- Jumlah Host = 2^(host bits) - 2
- Jumlah Subnet = 2^(subnet bits)
- Blok Size = 256 - nilai oktet terakhir subnet mask
3. Cara Menghitung Network Address, Broadcast, Host Range
Section titled “3. Cara Menghitung Network Address, Broadcast, Host Range”Langkah-langkah:
Section titled “Langkah-langkah:”Contoh: IP = 192.168.1.130, Subnet Mask = 255.255.255.192 (/26)
Langkah 1: Temukan blok size
Oktet terakhir subnet mask = 192Blok size = 256 - 192 = 64Blok-blok: 0, 64, 128, 192, 256...Langkah 2: Temukan network address
130 berada di antara 128 dan 192→ Network Address = 192.168.1.128Langkah 3: Hitung broadcast
Broadcast = Network Address + Blok Size - 1 = 128 + 64 - 1 = 191→ Broadcast = 192.168.1.191Langkah 4: Tentukan host range
Host pertama = Network Address + 1 = 192.168.1.129Host terakhir = Broadcast - 1 = 192.168.1.190Host range: 192.168.1.129 – 192.168.1.190Ringkasan:
| Info | Nilai |
|---|---|
| Network Address | 192.168.1.128 |
| Subnet Mask | 255.255.255.192 (/26) |
| Host Pertama | 192.168.1.129 |
| Host Terakhir | 192.168.1.190 |
| Broadcast | 192.168.1.191 |
| Jumlah Host | 62 |
4. Tabel Subnet Visual /24
Section titled “4. Tabel Subnet Visual /24”Network: 192.168.1.0/24 dibagi menjadi beberapa subnet:
Dibagi jadi 2 subnet (/25):
Section titled “Dibagi jadi 2 subnet (/25):”| Subnet | Network | Host Range | Broadcast |
|---|---|---|---|
| Subnet 1 | 192.168.1.0 | .1 – .126 | 192.168.1.127 |
| Subnet 2 | 192.168.1.128 | .129 – .254 | 192.168.1.255 |
Dibagi jadi 4 subnet (/26):
Section titled “Dibagi jadi 4 subnet (/26):”| Subnet | Network | Host Range | Broadcast |
|---|---|---|---|
| Subnet 1 | 192.168.1.0 | .1 – .62 | 192.168.1.63 |
| Subnet 2 | 192.168.1.64 | .65 – .126 | 192.168.1.127 |
| Subnet 3 | 192.168.1.128 | .129 – .190 | 192.168.1.191 |
| Subnet 4 | 192.168.1.192 | .193 – .254 | 192.168.1.255 |
Dibagi jadi 8 subnet (/27):
Section titled “Dibagi jadi 8 subnet (/27):”| Subnet | Network | Host Range | Broadcast |
|---|---|---|---|
| 1 | 192.168.1.0 | .1 – .30 | .31 |
| 2 | 192.168.1.32 | .33 – .62 | .63 |
| 3 | 192.168.1.64 | .65 – .94 | .95 |
| 4 | 192.168.1.96 | .97 – .126 | .127 |
| 5 | 192.168.1.128 | .129 – .158 | .159 |
| 6 | 192.168.1.160 | .161 – .190 | .191 |
| 7 | 192.168.1.192 | .193 – .222 | .223 |
| 8 | 192.168.1.224 | .225 – .254 | .255 |
5. Contoh Soal VLSM
Section titled “5. Contoh Soal VLSM”VLSM (Variable Length Subnet Mask) adalah teknik subnetting yang menggunakan subnet mask berbeda-beda sesuai kebutuhan host.
Sebuah SMK memiliki network 192.168.10.0/24. Bagi menjadi subnet untuk:
- Lab Komputer: 50 host
- Ruang Guru: 25 host
- Ruang TU: 10 host
- Link WAN Router-ISP: 2 host
Penyelesaian VLSM:
Section titled “Penyelesaian VLSM:”Urutkan dari kebutuhan host TERBESAR:
- Lab Komputer: 50 host → /26 (62 host)
- Ruang Guru: 25 host → /27 (30 host)
- Ruang TU: 10 host → /28 (14 host)
- Link WAN: 2 host → /30 (2 host)
Alokasi subnet:
| Departemen | Kebutuhan | CIDR | Network | Host Range | Broadcast |
|---|---|---|---|---|---|
| Lab Komputer | 50 host | /26 | 192.168.10.0 | .1 – .62 | 192.168.10.63 |
| Ruang Guru | 25 host | /27 | 192.168.10.64 | .65 – .94 | 192.168.10.95 |
| Ruang TU | 10 host | /28 | 192.168.10.96 | .97 – .110 | 192.168.10.111 |
| Link WAN | 2 host | /30 | 192.168.10.112 | .113 – .114 | 192.168.10.115 |
| Sisa (cadangan) | — | — | 192.168.10.116 | — | 192.168.10.255 |
6. Tabel CIDR Lengkap
Section titled “6. Tabel CIDR Lengkap”IPv4 CIDR Reference:
Section titled “IPv4 CIDR Reference:”| CIDR | Subnet Mask | Host Bits | Jumlah Host | Jumlah Alamat |
|---|---|---|---|---|
| /8 | 255.0.0.0 | 24 | 16,777,214 | 16,777,216 |
| /9 | 255.128.0.0 | 23 | 8,388,606 | 8,388,608 |
| /10 | 255.192.0.0 | 22 | 4,194,302 | 4,194,304 |
| /11 | 255.224.0.0 | 21 | 2,097,150 | 2,097,152 |
| /12 | 255.240.0.0 | 20 | 1,048,574 | 1,048,576 |
| /13 | 255.248.0.0 | 19 | 524,286 | 524,288 |
| /14 | 255.252.0.0 | 18 | 262,142 | 262,144 |
| /15 | 255.254.0.0 | 17 | 131,070 | 131,072 |
| /16 | 255.255.0.0 | 16 | 65,534 | 65,536 |
| /17 | 255.255.128.0 | 15 | 32,766 | 32,768 |
| /18 | 255.255.192.0 | 14 | 16,382 | 16,384 |
| /19 | 255.255.224.0 | 13 | 8,190 | 8,192 |
| /20 | 255.255.240.0 | 12 | 4,094 | 4,096 |
| /21 | 255.255.248.0 | 11 | 2,046 | 2,048 |
| /22 | 255.255.252.0 | 10 | 1,022 | 1,024 |
| /23 | 255.255.254.0 | 9 | 510 | 512 |
| /24 | 255.255.255.0 | 8 | 254 | 256 |
| /25 | 255.255.255.128 | 7 | 126 | 128 |
| /26 | 255.255.255.192 | 6 | 62 | 64 |
| /27 | 255.255.255.224 | 5 | 30 | 32 |
| /28 | 255.255.255.240 | 4 | 14 | 16 |
| /29 | 255.255.255.248 | 3 | 6 | 8 |
| /30 | 255.255.255.252 | 2 | 2 | 4 |
| /31 | 255.255.255.254 | 1 | 0 (point-to-point) | 2 |
| /32 | 255.255.255.255 | 0 | 1 (host route) | 1 |
7. Tips Cepat Subnetting
Section titled “7. Tips Cepat Subnetting”Rumus Cepat:
Section titled “Rumus Cepat:”| Yang dicari | Rumus |
|---|---|
| Jumlah host usable | 2^h - 2 (h = host bits) |
| Jumlah subnet | 2^s (s = subnet bits dipinjam) |
| Blok size | 256 - nilai oktet subnet mask |
| Network address | IP AND subnet mask |
| Broadcast | Network + blok size - 1 |
Trik Menghafal Blok Size:
Section titled “Trik Menghafal Blok Size:”/25 → 128 (256/2)/26 → 64 (256/4)/27 → 32 (256/8)/28 → 16 (256/16)/29 → 8 (256/32)/30 → 4 (256/64)Nilai Oktet Subnet Mask → CIDR:
Section titled “Nilai Oktet Subnet Mask → CIDR:”| Nilai | CIDR (oktet 4) |
|---|---|
| 0 | /24 |
| 128 | /25 |
| 192 | /26 |
| 224 | /27 |
| 240 | /28 |
| 248 | /29 |
| 252 | /30 |
| 254 | /31 |
| 255 | /32 |